3(3m-2)=2(2m+5)

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Solution for 3(3m-2)=2(2m+5) equation: 



3(3m-2)=2(2m+5)

We move all terms to the left:

3(3m-2)-(2(2m+5))=0

We multiply parentheses

9m-(2(2m+5))-6=0



We calculate terms in parentheses: -(2(2m+5)), so:

2(2m+5)

We multiply parentheses

4m+10

Back to the equation:

-(4m+10)



We get rid of parentheses

9m-4m-10-6=0

We add all the numbers together, and all the variables

5m-16=0

We move all terms containing m to the left, all other terms to the right

5m=16

m=16/5

m=3+1/5

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