3(3m-3)=3(m+65)

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Solution for 3(3m-3)=3(m+65) equation: 



3(3m-3)=3(m+65)

We move all terms to the left:

3(3m-3)-(3(m+65))=0

We multiply parentheses

9m-(3(m+65))-9=0



We calculate terms in parentheses: -(3(m+65)), so:

3(m+65)

We multiply parentheses

3m+195

Back to the equation:

-(3m+195)



We get rid of parentheses

9m-3m-195-9=0

We add all the numbers together, and all the variables

6m-204=0

We move all terms containing m to the left, all other terms to the right

6m=204

m=204/6

m=34

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