3(3m-5)=9-10(-10-4m)

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Solution for 3(3m-5)=9-10(-10-4m) equation: 



3(3m-5)=9-10(-10-4m)

We move all terms to the left:

3(3m-5)-(9-10(-10-4m))=0

We add all the numbers together, and all the variables

3(3m-5)-(9-10(-4m-10))=0

We multiply parentheses

9m-(9-10(-4m-10))-15=0



We calculate terms in parentheses: -(9-10(-4m-10)), so:

9-10(-4m-10)

determiningTheFunctionDomain
-10(-4m-10)+9

We multiply parentheses

40m+100+9

We add all the numbers together, and all the variables

40m+109

Back to the equation:

-(40m+109)



We get rid of parentheses

9m-40m-109-15=0

We add all the numbers together, and all the variables

-31m-124=0

We move all terms containing m to the left, all other terms to the right

-31m=124

m=124/-31

m=-4

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