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3(3n+n)=2(n+5)
We move all terms to the left:
3(3n+n)-(2(n+5))=0
We add all the numbers together, and all the variables
3(+4n)-(2(n+5))=0
We multiply parentheses
12n-(2(n+5))=0
We calculate terms in parentheses: -(2(n+5)), so:We get rid of parentheses
2(n+5)
We multiply parentheses
2n+10
Back to the equation:
-(2n+10)
12n-2n-10=0
We add all the numbers together, and all the variables
10n-10=0
We move all terms containing n to the left, all other terms to the right
10n=10
n=10/10
n=1
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