3(3n-2)=2(3n+3)

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Solution for 3(3n-2)=2(3n+3) equation:



3(3n-2)=2(3n+3)
We move all terms to the left:
3(3n-2)-(2(3n+3))=0
We multiply parentheses
9n-(2(3n+3))-6=0
We calculate terms in parentheses: -(2(3n+3)), so:
2(3n+3)
We multiply parentheses
6n+6
Back to the equation:
-(6n+6)
We get rid of parentheses
9n-6n-6-6=0
We add all the numbers together, and all the variables
3n-12=0
We move all terms containing n to the left, all other terms to the right
3n=12
n=12/3
n=4

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