3(3q-2)=2(2q-5)

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Solution for 3(3q-2)=2(2q-5) equation: 



3(3q-2)=2(2q-5)

We move all terms to the left:

3(3q-2)-(2(2q-5))=0

We multiply parentheses

9q-(2(2q-5))-6=0



We calculate terms in parentheses: -(2(2q-5)), so:

2(2q-5)

We multiply parentheses

4q-10

Back to the equation:

-(4q-10)



We get rid of parentheses

9q-4q+10-6=0

We add all the numbers together, and all the variables

5q+4=0

We move all terms containing q to the left, all other terms to the right

5q=-4

q=-4/5

q=-4/5

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