3(3r+2)-(1r-6)=13

Solution for 3(3r+2)-(1r-6)=13 equation:

Simplifying
3(3r + 2) + -1(1r + -6) = 13

Reorder the terms:
3(2 + 3r) + -1(1r + -6) = 13
(2 * 3 + 3r * 3) + -1(1r + -6) = 13
(6 + 9r) + -1(1r + -6) = 13

Reorder the terms:
6 + 9r + -1(-6 + 1r) = 13
6 + 9r + (-6 * -1 + 1r * -1) = 13
6 + 9r + (6 + -1r) = 13

Reorder the terms:
6 + 6 + 9r + -1r = 13

Combine like terms: 6 + 6 = 12
12 + 9r + -1r = 13

Combine like terms: 9r + -1r = 8r
12 + 8r = 13

Solving
12 + 8r = 13

Solving for variable 'r'.

Move all terms containing r to the left, all other terms to the right.

Add '-12' to each side of the equation.
12 + -12 + 8r = 13 + -12

Combine like terms: 12 + -12 = 0
0 + 8r = 13 + -12
8r = 13 + -12

Combine like terms: 13 + -12 = 1
8r = 1

Divide each side by '8'.
r = 0.125

Simplifying
r = 0.125