3(3r-2)+7(-r+3)=34

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Solution for 3(3r-2)+7(-r+3)=34 equation: 



3(3r-2)+7(-r+3)=34

We move all terms to the left:

3(3r-2)+7(-r+3)-(34)=0

We add all the numbers together, and all the variables

3(3r-2)+7(-1r+3)-34=0

We multiply parentheses

9r-7r-6+21-34=0

We add all the numbers together, and all the variables

2r-19=0

We move all terms containing r to the left, all other terms to the right

2r=19

r=19/2

r=9+1/2

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