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3(3r-r)+3(r+1)=12
We move all terms to the left:
3(3r-r)+3(r+1)-(12)=0
We add all the numbers together, and all the variables
3(+2r)+3(r+1)-12=0
We multiply parentheses
6r+3r+3-12=0
We add all the numbers together, and all the variables
9r-9=0
We move all terms containing r to the left, all other terms to the right
9r=9
r=9/9
r=1
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