3(3t+1)-16=t-(t+12)

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Solution for 3(3t+1)-16=t-(t+12) equation: 



3(3t+1)-16=t-(t+12)

We move all terms to the left:

3(3t+1)-16-(t-(t+12))=0

We multiply parentheses

9t-(t-(t+12))+3-16=0



We calculate terms in parentheses: -(t-(t+12)), so:

t-(t+12)

We get rid of parentheses

t-t-12

We add all the numbers together, and all the variables

-12

Back to the equation:

-(-12)



We add all the numbers together, and all the variables

9t-1=0

We move all terms containing t to the left, all other terms to the right

9t=1

t=1/9

t=1/9

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