3(3t-2)=4(7t-1)

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Solution for 3(3t-2)=4(7t-1) equation: 



3(3t-2)=4(7t-1)

We move all terms to the left:

3(3t-2)-(4(7t-1))=0

We multiply parentheses

9t-(4(7t-1))-6=0



We calculate terms in parentheses: -(4(7t-1)), so:

4(7t-1)

We multiply parentheses

28t-4

Back to the equation:

-(28t-4)



We get rid of parentheses

9t-28t+4-6=0

We add all the numbers together, and all the variables

-19t-2=0

We move all terms containing t to the left, all other terms to the right

-19t=2

t=2/-19

t=-2/19

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