3(3u+1)=3(u-2)-3

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Solution for 3(3u+1)=3(u-2)-3 equation: 



3(3u+1)=3(u-2)-3

We move all terms to the left:

3(3u+1)-(3(u-2)-3)=0

We multiply parentheses

9u-(3(u-2)-3)+3=0



We calculate terms in parentheses: -(3(u-2)-3), so:

3(u-2)-3

We multiply parentheses

3u-6-3

We add all the numbers together, and all the variables

3u-9

Back to the equation:

-(3u-9)



We get rid of parentheses

9u-3u+9+3=0

We add all the numbers together, and all the variables

6u+12=0

We move all terms containing u to the left, all other terms to the right

6u=-12

u=-12/6

u=-2

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