3(3u-3)=4(u+3)

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Solution for 3(3u-3)=4(u+3) equation: 



3(3u-3)=4(u+3)

We move all terms to the left:

3(3u-3)-(4(u+3))=0

We multiply parentheses

9u-(4(u+3))-9=0



We calculate terms in parentheses: -(4(u+3)), so:

4(u+3)

We multiply parentheses

4u+12

Back to the equation:

-(4u+12)



We get rid of parentheses

9u-4u-12-9=0

We add all the numbers together, and all the variables

5u-21=0

We move all terms containing u to the left, all other terms to the right

5u=21

u=21/5

u=4+1/5

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