3(3v+1)+4v+2=5(v-5)+3v

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Solution for 3(3v+1)+4v+2=5(v-5)+3v equation: 



3(3v+1)+4v+2=5(v-5)+3v

We move all terms to the left:

3(3v+1)+4v+2-(5(v-5)+3v)=0

We add all the numbers together, and all the variables

4v+3(3v+1)-(5(v-5)+3v)+2=0

We multiply parentheses

4v+9v-(5(v-5)+3v)+3+2=0



We calculate terms in parentheses: -(5(v-5)+3v), so:

5(v-5)+3v

We add all the numbers together, and all the variables

3v+5(v-5)

We multiply parentheses

3v+5v-25

We add all the numbers together, and all the variables

8v-25

Back to the equation:

-(8v-25)



We add all the numbers together, and all the variables

13v-(8v-25)+5=0

We get rid of parentheses

13v-8v+25+5=0

We add all the numbers together, and all the variables

5v+30=0

We move all terms containing v to the left, all other terms to the right

5v=-30

v=-30/5

v=-6

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