3(3w-2)-21=3(w+1)+30

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Solution for 3(3w-2)-21=3(w+1)+30 equation: 



3(3w-2)-21=3(w+1)+30

We move all terms to the left:

3(3w-2)-21-(3(w+1)+30)=0

We multiply parentheses

9w-(3(w+1)+30)-6-21=0



We calculate terms in parentheses: -(3(w+1)+30), so:

3(w+1)+30

We multiply parentheses

3w+3+30

We add all the numbers together, and all the variables

3w+33

Back to the equation:

-(3w+33)



We add all the numbers together, and all the variables

9w-(3w+33)-27=0

We get rid of parentheses

9w-3w-33-27=0

We add all the numbers together, and all the variables

6w-60=0

We move all terms containing w to the left, all other terms to the right

6w=60

w=60/6

w=10

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