3(3x+-2)=4(3+x)

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Solution for 3(3x+-2)=4(3+x) equation: 



3(3x+-2)=4(3+x)

We move all terms to the left:

3(3x+-2)-(4(3+x))=0

We add all the numbers together, and all the variables

3(3x-2)-(4(x+3))=0

We multiply parentheses

9x-(4(x+3))-6=0



We calculate terms in parentheses: -(4(x+3)), so:

4(x+3)

We multiply parentheses

4x+12

Back to the equation:

-(4x+12)



We get rid of parentheses

9x-4x-12-6=0

We add all the numbers together, and all the variables

5x-18=0

We move all terms containing x to the left, all other terms to the right

5x=18

x=18/5

x=3+3/5

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