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3(3x+1)-2(2x-2)=5(x-3)
We move all terms to the left:
3(3x+1)-2(2x-2)-(5(x-3))=0
We multiply parentheses
9x-4x-(5(x-3))+3+4=0
We calculate terms in parentheses: -(5(x-3)), so:We add all the numbers together, and all the variables
5(x-3)
We multiply parentheses
5x-15
Back to the equation:
-(5x-15)
5x-(5x-15)+7=0
We get rid of parentheses
5x-5x+15+7=0
We add all the numbers together, and all the variables
22!=0
There is no solution for this equation
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