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3(3x+1)-5=-2(x+5)+4x
We move all terms to the left:
3(3x+1)-5-(-2(x+5)+4x)=0
We multiply parentheses
9x-(-2(x+5)+4x)+3-5=0
We calculate terms in parentheses: -(-2(x+5)+4x), so:We add all the numbers together, and all the variables
-2(x+5)+4x
We add all the numbers together, and all the variables
4x-2(x+5)
We multiply parentheses
4x-2x-10
We add all the numbers together, and all the variables
2x-10
Back to the equation:
-(2x-10)
9x-(2x-10)-2=0
We get rid of parentheses
9x-2x+10-2=0
We add all the numbers together, and all the variables
7x+8=0
We move all terms containing x to the left, all other terms to the right
7x=-8
x=-8/7
x=-1+1/7
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