3(3x+1)=-3(2x-3)-2x

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Solution for 3(3x+1)=-3(2x-3)-2x equation: 



3(3x+1)=-3(2x-3)-2x

We move all terms to the left:

3(3x+1)-(-3(2x-3)-2x)=0

We multiply parentheses

9x-(-3(2x-3)-2x)+3=0



We calculate terms in parentheses: -(-3(2x-3)-2x), so:

-3(2x-3)-2x

We add all the numbers together, and all the variables

-2x-3(2x-3)

We multiply parentheses

-2x-6x+9

We add all the numbers together, and all the variables

-8x+9

Back to the equation:

-(-8x+9)



We get rid of parentheses

9x+8x-9+3=0

We add all the numbers together, and all the variables

17x-6=0

We move all terms containing x to the left, all other terms to the right

17x=6

x=6/17

x=6/17

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