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3(3x+1)=-3(5x-5)-5x
We move all terms to the left:
3(3x+1)-(-3(5x-5)-5x)=0
We multiply parentheses
9x-(-3(5x-5)-5x)+3=0
We calculate terms in parentheses: -(-3(5x-5)-5x), so:We get rid of parentheses
-3(5x-5)-5x
We add all the numbers together, and all the variables
-5x-3(5x-5)
We multiply parentheses
-5x-15x+15
We add all the numbers together, and all the variables
-20x+15
Back to the equation:
-(-20x+15)
9x+20x-15+3=0
We add all the numbers together, and all the variables
29x-12=0
We move all terms containing x to the left, all other terms to the right
29x=12
x=12/29
x=12/29
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