3(3x+1)=1+5(x-2)

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Solution for 3(3x+1)=1+5(x-2) equation: 



3(3x+1)=1+5(x-2)

We move all terms to the left:

3(3x+1)-(1+5(x-2))=0

We multiply parentheses

9x-(1+5(x-2))+3=0



We calculate terms in parentheses: -(1+5(x-2)), so:

1+5(x-2)

determiningTheFunctionDomain
5(x-2)+1

We multiply parentheses

5x-10+1

We add all the numbers together, and all the variables

5x-9

Back to the equation:

-(5x-9)



We get rid of parentheses

9x-5x+9+3=0

We add all the numbers together, and all the variables

4x+12=0

We move all terms containing x to the left, all other terms to the right

4x=-12

x=-12/4

x=-3

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