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3(3x+1)=4(x+10)
We move all terms to the left:
3(3x+1)-(4(x+10))=0
We multiply parentheses
9x-(4(x+10))+3=0
We calculate terms in parentheses: -(4(x+10)), so:We get rid of parentheses
4(x+10)
We multiply parentheses
4x+40
Back to the equation:
-(4x+40)
9x-4x-40+3=0
We add all the numbers together, and all the variables
5x-37=0
We move all terms containing x to the left, all other terms to the right
5x=37
x=37/5
x=7+2/5
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