3(3x+1)=6x+20

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Solution for 3(3x+1)=6x+20 equation: 



3(3x+1)=6x+20

We move all terms to the left:

3(3x+1)-(6x+20)=0

We multiply parentheses

9x-(6x+20)+3=0

We get rid of parentheses

9x-6x-20+3=0

We add all the numbers together, and all the variables

3x-17=0

We move all terms containing x to the left, all other terms to the right

3x=17

x=17/3

x=5+2/3

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