3(3x+1)=x+33

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Solution for 3(3x+1)=x+33 equation: 



3(3x+1)=x+33

We move all terms to the left:

3(3x+1)-(x+33)=0

We multiply parentheses

9x-(x+33)+3=0

We get rid of parentheses

9x-x-33+3=0

We add all the numbers together, and all the variables

8x-30=0

We move all terms containing x to the left, all other terms to the right

8x=30

x=30/8

x=3+3/4

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