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3(3x+12)=5(x+20)
We move all terms to the left:
3(3x+12)-(5(x+20))=0
We multiply parentheses
9x-(5(x+20))+36=0
We calculate terms in parentheses: -(5(x+20)), so:We get rid of parentheses
5(x+20)
We multiply parentheses
5x+100
Back to the equation:
-(5x+100)
9x-5x-100+36=0
We add all the numbers together, and all the variables
4x-64=0
We move all terms containing x to the left, all other terms to the right
4x=64
x=64/4
x=16
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