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3(3x+15)=6(x+2)
We move all terms to the left:
3(3x+15)-(6(x+2))=0
We multiply parentheses
9x-(6(x+2))+45=0
We calculate terms in parentheses: -(6(x+2)), so:We get rid of parentheses
6(x+2)
We multiply parentheses
6x+12
Back to the equation:
-(6x+12)
9x-6x-12+45=0
We add all the numbers together, and all the variables
3x+33=0
We move all terms containing x to the left, all other terms to the right
3x=-33
x=-33/3
x=-11
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