3(3x+2)+20x=48-x

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Solution for 3(3x+2)+20x=48-x equation: 



3(3x+2)+20x=48-x

We move all terms to the left:

3(3x+2)+20x-(48-x)=0

We add all the numbers together, and all the variables

3(3x+2)+20x-(-1x+48)=0

We add all the numbers together, and all the variables

20x+3(3x+2)-(-1x+48)=0

We multiply parentheses

20x+9x-(-1x+48)+6=0

We get rid of parentheses

20x+9x+1x-48+6=0

We add all the numbers together, and all the variables

30x-42=0

We move all terms containing x to the left, all other terms to the right

30x=42

x=42/30

x=1+2/5

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