3(3x+2)2x=7x+6

Solution for 3(3x+2)2x=7x+6 equation:

3(3x+2)2x=7x+6

We move all terms to the left:

3(3x+2)2x-(7x+6)=0

We multiply parentheses

18x^2+12x-(7x+6)=0

We get rid of parentheses

18x^2+12x-7x-6=0

We add all the numbers together, and all the variables

18x^2+5x-6=0

a = 18; b = 5; c = -6;
Δ = b2-4ac
Δ = 52-4·18·(-6)
Δ = 457
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{457}}{2*18}=\frac{-5-\sqrt{457}}{36}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{457}}{2*18}=\frac{-5+\sqrt{457}}{36}
$