3(3x+2)=2(4x-4)+20

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Solution for 3(3x+2)=2(4x-4)+20 equation: 



3(3x+2)=2(4x-4)+20

We move all terms to the left:

3(3x+2)-(2(4x-4)+20)=0

We multiply parentheses

9x-(2(4x-4)+20)+6=0



We calculate terms in parentheses: -(2(4x-4)+20), so:

2(4x-4)+20

We multiply parentheses

8x-8+20

We add all the numbers together, and all the variables

8x+12

Back to the equation:

-(8x+12)



We get rid of parentheses

9x-8x-12+6=0

We add all the numbers together, and all the variables

x-6=0

We move all terms containing x to the left, all other terms to the right

x=6

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