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3(3x+2)=4(2x+5)
We move all terms to the left:
3(3x+2)-(4(2x+5))=0
We multiply parentheses
9x-(4(2x+5))+6=0
We calculate terms in parentheses: -(4(2x+5)), so:We get rid of parentheses
4(2x+5)
We multiply parentheses
8x+20
Back to the equation:
-(8x+20)
9x-8x-20+6=0
We add all the numbers together, and all the variables
x-14=0
We move all terms containing x to the left, all other terms to the right
x=14
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