3(3x+21)=2(x+35)

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Solution for 3(3x+21)=2(x+35) equation: 



3(3x+21)=2(x+35)

We move all terms to the left:

3(3x+21)-(2(x+35))=0

We multiply parentheses

9x-(2(x+35))+63=0



We calculate terms in parentheses: -(2(x+35)), so:

2(x+35)

We multiply parentheses

2x+70

Back to the equation:

-(2x+70)



We get rid of parentheses

9x-2x-70+63=0

We add all the numbers together, and all the variables

7x-7=0

We move all terms containing x to the left, all other terms to the right

7x=7

x=7/7

x=1

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