3(3x+3)-4(5x-3)=x(x-3)-x(x+5)

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Solution for 3(3x+3)-4(5x-3)=x(x-3)-x(x+5) equation: 



3(3x+3)-4(5x-3)=x(x-3)-x(x+5)

We move all terms to the left:

3(3x+3)-4(5x-3)-(x(x-3)-x(x+5))=0

We multiply parentheses

9x-20x-(x(x-3)-x(x+5))+9+12=0



We calculate terms in parentheses: -(x(x-3)-x(x+5)), so:

x(x-3)-x(x+5)

We multiply parentheses

x^2-x^2-3x-5x

We add all the numbers together, and all the variables

-8x

Back to the equation:

-(-8x)



We add all the numbers together, and all the variables

-11x-(-8x)+21=0

We get rid of parentheses

-11x+8x+21=0

We add all the numbers together, and all the variables

-3x+21=0

We move all terms containing x to the left, all other terms to the right

-3x=-21

x=-21/-3

x=+7

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