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3(3x+3)10x+x-1=108
We move all terms to the left:
3(3x+3)10x+x-1-(108)=0
We add all the numbers together, and all the variables
x+3(3x+3)10x-109=0
We multiply parentheses
90x^2+x+90x-109=0
We add all the numbers together, and all the variables
90x^2+91x-109=0
a = 90; b = 91; c = -109;
Δ = b2-4ac
Δ = 912-4·90·(-109)
Δ = 47521
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(91)-\sqrt{47521}}{2*90}=\frac{-91-\sqrt{47521}}{180} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(91)+\sqrt{47521}}{2*90}=\frac{-91+\sqrt{47521}}{180} $
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