3(3x+3)=x+33

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Solution for 3(3x+3)=x+33 equation: 



3(3x+3)=x+33

We move all terms to the left:

3(3x+3)-(x+33)=0

We multiply parentheses

9x-(x+33)+9=0

We get rid of parentheses

9x-x-33+9=0

We add all the numbers together, and all the variables

8x-24=0

We move all terms containing x to the left, all other terms to the right

8x=24

x=24/8

x=3

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