3(3x+35)=2(x+21)

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Solution for 3(3x+35)=2(x+21) equation: 



3(3x+35)=2(x+21)

We move all terms to the left:

3(3x+35)-(2(x+21))=0

We multiply parentheses

9x-(2(x+21))+105=0



We calculate terms in parentheses: -(2(x+21)), so:

2(x+21)

We multiply parentheses

2x+42

Back to the equation:

-(2x+42)



We get rid of parentheses

9x-2x-42+105=0

We add all the numbers together, and all the variables

7x+63=0

We move all terms containing x to the left, all other terms to the right

7x=-63

x=-63/7

x=-9

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