3(3x+4)5=9x+(-2)

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Solution for 3(3x+4)5=9x+(-2) equation: 



3(3x+4)5=9x+(-2)

We move all terms to the left:

3(3x+4)5-(9x+(-2))=0

We multiply parentheses

45x-(9x+(-2))+60=0



We calculate terms in parentheses: -(9x+(-2)), so:

9x+(-2)

We add all the numbers together, and all the variables

9x-2

Back to the equation:

-(9x-2)



We get rid of parentheses

45x-9x+2+60=0

We add all the numbers together, and all the variables

36x+62=0

We move all terms containing x to the left, all other terms to the right

36x=-62

x=-62/36

x=-1+13/18

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