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3(3x+4)=15+3(3x-1)
We move all terms to the left:
3(3x+4)-(15+3(3x-1))=0
We multiply parentheses
9x-(15+3(3x-1))+12=0
We calculate terms in parentheses: -(15+3(3x-1)), so:We get rid of parentheses
15+3(3x-1)
determiningTheFunctionDomain 3(3x-1)+15
We multiply parentheses
9x-3+15
We add all the numbers together, and all the variables
9x+12
Back to the equation:
-(9x+12)
9x-9x-12+12=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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