3(3x+4)=8(2X2)

Solution for 3(3x+4)=8(2X2) equation:

3(3x+4)=8(2x^2)

We move all terms to the left:

3(3x+4)-(8(2x^2))=0

determiningTheFunctionDomain
3(3x+4)-82x^2=0

We add all the numbers together, and all the variables

-82x^2+3(3x+4)=0

We multiply parentheses

-82x^2+9x+12=0

a = -82; b = 9; c = +12;
Δ = b2-4ac
Δ = 92-4·(-82)·12
Δ = 4017
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{4017}}{2*-82}=\frac{-9-\sqrt{4017}}{-164}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{4017}}{2*-82}=\frac{-9+\sqrt{4017}}{-164}
$