3(3x+5)+1=2(x-20)

Solution for 3(3x+5)+1=2(x-20) equation:

3(3x+5)+1=2(x-20)

We move all terms to the left:

3(3x+5)+1-(2(x-20))=0

We multiply parentheses

9x-(2(x-20))+15+1=0


We calculate terms in parentheses: -(2(x-20)), so:

2(x-20)

We multiply parentheses

2x-40

Back to the equation:

-(2x-40)


We add all the numbers together, and all the variables

9x-(2x-40)+16=0

We get rid of parentheses

9x-2x+40+16=0

We add all the numbers together, and all the variables

7x+56=0

We move all terms containing x to the left, all other terms to the right

7x=-56

x=-56/7

x=-8