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3(3x+5)=2(2x+5)
We move all terms to the left:
3(3x+5)-(2(2x+5))=0
We multiply parentheses
9x-(2(2x+5))+15=0
We calculate terms in parentheses: -(2(2x+5)), so:We get rid of parentheses
2(2x+5)
We multiply parentheses
4x+10
Back to the equation:
-(4x+10)
9x-4x-10+15=0
We add all the numbers together, and all the variables
5x+5=0
We move all terms containing x to the left, all other terms to the right
5x=-5
x=-5/5
x=-1
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