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3(3x+5)=6(5x-2)
We move all terms to the left:
3(3x+5)-(6(5x-2))=0
We multiply parentheses
9x-(6(5x-2))+15=0
We calculate terms in parentheses: -(6(5x-2)), so:We get rid of parentheses
6(5x-2)
We multiply parentheses
30x-12
Back to the equation:
-(30x-12)
9x-30x+12+15=0
We add all the numbers together, and all the variables
-21x+27=0
We move all terms containing x to the left, all other terms to the right
-21x=-27
x=-27/-21
x=1+2/7
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