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3(3x+6)=12x-(1+4x)
We move all terms to the left:
3(3x+6)-(12x-(1+4x))=0
We add all the numbers together, and all the variables
3(3x+6)-(12x-(4x+1))=0
We multiply parentheses
9x-(12x-(4x+1))+18=0
We calculate terms in parentheses: -(12x-(4x+1)), so:We get rid of parentheses
12x-(4x+1)
We get rid of parentheses
12x-4x-1
We add all the numbers together, and all the variables
8x-1
Back to the equation:
-(8x-1)
9x-8x+1+18=0
We add all the numbers together, and all the variables
x+19=0
We move all terms containing x to the left, all other terms to the right
x=-19
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