3(3x+7)+23=7(9x-78)+5

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Solution for 3(3x+7)+23=7(9x-78)+5 equation: 



3(3x+7)+23=7(9x-78)+5

We move all terms to the left:

3(3x+7)+23-(7(9x-78)+5)=0

We multiply parentheses

9x-(7(9x-78)+5)+21+23=0



We calculate terms in parentheses: -(7(9x-78)+5), so:

7(9x-78)+5

We multiply parentheses

63x-546+5

We add all the numbers together, and all the variables

63x-541

Back to the equation:

-(63x-541)



We add all the numbers together, and all the variables

9x-(63x-541)+44=0

We get rid of parentheses

9x-63x+541+44=0

We add all the numbers together, and all the variables

-54x+585=0

We move all terms containing x to the left, all other terms to the right

-54x=-585

x=-585/-54

x=10+5/6

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