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3(3x+9)=6(x+6)+3x-9
We move all terms to the left:
3(3x+9)-(6(x+6)+3x-9)=0
We multiply parentheses
9x-(6(x+6)+3x-9)+27=0
We calculate terms in parentheses: -(6(x+6)+3x-9), so:We get rid of parentheses
6(x+6)+3x-9
We add all the numbers together, and all the variables
3x+6(x+6)-9
We multiply parentheses
3x+6x+36-9
We add all the numbers together, and all the variables
9x+27
Back to the equation:
-(9x+27)
9x-9x-27+27=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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