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3(3x-1)+2=3(-3x+1)-4
We move all terms to the left:
3(3x-1)+2-(3(-3x+1)-4)=0
We multiply parentheses
9x-(3(-3x+1)-4)-3+2=0
We calculate terms in parentheses: -(3(-3x+1)-4), so:We add all the numbers together, and all the variables
3(-3x+1)-4
We multiply parentheses
-9x+3-4
We add all the numbers together, and all the variables
-9x-1
Back to the equation:
-(-9x-1)
9x-(-9x-1)-1=0
We get rid of parentheses
9x+9x+1-1=0
We add all the numbers together, and all the variables
18x=0
x=0/18
x=0
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