3(3x-1)-(6x-5)=x-2(x+1)

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Solution for 3(3x-1)-(6x-5)=x-2(x+1) equation: 



3(3x-1)-(6x-5)=x-2(x+1)

We move all terms to the left:

3(3x-1)-(6x-5)-(x-2(x+1))=0

We multiply parentheses

9x-(6x-5)-(x-2(x+1))-3=0

We get rid of parentheses

9x-6x-(x-2(x+1))+5-3=0



We calculate terms in parentheses: -(x-2(x+1)), so:

x-2(x+1)

We multiply parentheses

x-2x-2

We add all the numbers together, and all the variables

-1x-2

Back to the equation:

-(-1x-2)



We add all the numbers together, and all the variables

3x-(-1x-2)+2=0

We get rid of parentheses

3x+1x+2+2=0

We add all the numbers together, and all the variables

4x+4=0

We move all terms containing x to the left, all other terms to the right

4x=-4

x=-4/4

x=-1

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