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3(3x-1)=4(x+)
We move all terms to the left:
3(3x-1)-(4(x+))=0
We add all the numbers together, and all the variables
3(3x-1)-(4(+x))=0
We multiply parentheses
9x-(4(+x))-3=0
We calculate terms in parentheses: -(4(+x)), so:We add all the numbers together, and all the variables
4(+x)
We multiply parentheses
4x
Back to the equation:
-(4x)
5x-3=0
We move all terms containing x to the left, all other terms to the right
5x=3
x=3/5
x=3/5
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