3(3x-1)=5(2x+2)/2

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Solution for 3(3x-1)=5(2x+2)/2 equation: 



3(3x-1)=5(2x+2)/2

We move all terms to the left:

3(3x-1)-(5(2x+2)/2)=0

We multiply parentheses

9x-(5(2x+2)/2)-3=0

We multiply all the terms by the denominator


9x*2)-(5(2x+2)-3*2)=0

We add all the numbers together, and all the variables

9x*2)-(5(2x+2)=0

Wy multiply elements

18x^2=0

a = 18; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·18·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{36}=0$

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