3(3x-2)+12+4x=3

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Solution for 3(3x-2)+12+4x=3 equation: 



3(3x-2)+12+4x=3

We move all terms to the left:

3(3x-2)+12+4x-(3)=0

We add all the numbers together, and all the variables

4x+3(3x-2)+9=0

We multiply parentheses

4x+9x-6+9=0

We add all the numbers together, and all the variables

13x+3=0

We move all terms containing x to the left, all other terms to the right

13x=-3

x=-3/13

x=-3/13

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