3(3x-2)+12+4x=3

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Solution for 3(3x-2)+12+4x=3 equation:



3(3x-2)+12+4x=3
We move all terms to the left:
3(3x-2)+12+4x-(3)=0
We add all the numbers together, and all the variables
4x+3(3x-2)+9=0
We multiply parentheses
4x+9x-6+9=0
We add all the numbers together, and all the variables
13x+3=0
We move all terms containing x to the left, all other terms to the right
13x=-3
x=-3/13
x=-3/13

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