3(3x-2)+12=-30

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Solution for 3(3x-2)+12=-30 equation: 



3(3x-2)+12=-30

We move all terms to the left:

3(3x-2)+12-(-30)=0

We add all the numbers together, and all the variables

3(3x-2)+42=0

We multiply parentheses

9x-6+42=0

We add all the numbers together, and all the variables

9x+36=0

We move all terms containing x to the left, all other terms to the right

9x=-36

x=-36/9

x=-4

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